Unless you’re a complete masochist, you’re doing to want to split this into a more manageable data set, otherwise you’re gonna eat all the memory on your server. But this means that you can no longer use the DataSet.Tables[0].Rows.Count property to figure out how many rows you have. You can write a second stored procedure that’ll count the rows. But who wants to clog up their database with tons of stored procedures for no reason? Let’s consolidate it into one.

So what does this look like?

First: the stored procedure.

We’ll use output parameters to pass the row count back to our code


create procedure [dbo].[Search]
@searchText varchar(512), @recordsToReturn INT, @pageNumber INT, @numberofrows INT OUTPUT
AS

Now the C# (this’ll work in VB too, but feel free to convert it yourself)


SqlConnection conn = new SqlConnection();
conn.ConnectionString = ".....your connection string here.....";
conn.Open();

da.Dispose();
conn.Close();


Best of luck! As always, leave a message in the comments if you have questions

It seems the fastest way to do this is simply to:

delete from [table] where creation_timestamp < dateadd (mm, -6, getdate())

(deleting anything older than 6 months)

It took 3 hours (10916 seconds to be exact) to delete 1.6 million (1,619,433) records this way. (148.35 / second).

We needed to do a second batch the next day, but wanted to split it into batches to try to get better performance.

Running:


delete from [table] where pk_id in(
select pk_id from (
SELECT ROW_NUMBER() OVER (ORDER BY creation_timestamp desc) AS RowNumber, pk_id
FROM [table]
where creation_timestamp < '2009-12-16 13:52:08.673') _objectsToDelete
WHERE RowNumber between 1 and 100000)


takes 12 minutes. (732 seconds) (136.61 / second).

Strangely, using the TOP command with a subquery takes the longest:


delete from [table] where pk_id in (select TOP 100000 pk_id from [table] where creation_timestamp < '2009-12-16 13:52:08.673')


15 minutes (904 seconds) (110.61 / second)

Have a better way? Let me know in the comments!

Today, while working on a pretty simple plugin, I wanted to add this functionality, and I didn’t want to waste a bunch of time. I was given a link to this great script: http://www.warkensoft.com/2009/12/paginated-navigation-bar/

It took me about a minute to implement the functionality. I then spent another 5 minutes doing CSS and that was it. Done. I’m not usually one for link sharing, but this made my life much easier. Hopefully it can make yours easier too.

The solution is pure PHP, no javascript required. Some day, I may try to expand upon this to include javascripty goodness, because that’s pretty much the only thing that could make it better

you get a message something like:

-bash: mysqldump: command not found


so how do you fix this? well, copy and paste the following into your terminal window and press enter:

echo export PATH="/usr/local/bin:/usr/local/sbin:/usr/local/mysql/bin:$PATH" >> ~/.profile

source ~/.profile


whoa, whoa, you say. what is this doing? It makes it so that when you type any command into the terminal, it does a check of these folders before giving you the “command not found” error.

If you want to undo it, you can always edit your .profile, or just delete it.

Assuming everything else works, this should solve your problem!

1. go to google maps, type the address, and click search
2. once you’ve found it, go to your address bar and clear what’s in it
3. paste: javascript:void(prompt('',gApplication.getMap().getCenter())); into the address bar
4. use the coordinates for whatever you wish!

if you’re using the new version of VirtualHostX, make sure that you select Directory from the dropdown, then use:


Options FollowSymLinks
AllowOverride All AuthConfig



Then I messed around in IE, trying to make it work, even downloading this tool:

Worst thing EVER. Don’t do this. Don’t get this. Don’t even look at this. You will feel violated if you use it.

So…how to embed an OTF font in a website (make sure you have a license to do so kids):

1. Convert OTF file to .ttf (use fontForge)
2. Embed with @font-face
3. When adding the font to a style, in IE you CAN NOT call it by the name you gave it with the @font-face declaration. You have to call it by it’s name. So if the font’s name is myfontLTSTDBOLDITALICROMAN you have to do: body{ font-family: myfontLTSTDBOLDITALICROMAN; } Sucky? Very. Works? yes.

Have a nice day